Question 1

Using 128-bit addresses provides approximately $10 ^ { x }$ unique address, where x= _______.

Accepted Answer

$2 ^ { 128 } = 2 ^ { 8 } \left( 2 ^ { 10 } \right) ^ { 12 } = 256 \left( 10 ^ { 3 } \right) ^ { 12 } = 256 \times 10 ^ { 36 } = 2.56 \times 10 ^ { 38 }$

Question 2

A 512-bit data file is to be transferred with asynchronous transmission packets that each contain a start bit, an 8-bit data byte, a parity bit, and one stop bit.How many bits are transmitted over achannel?

Accepted Answer

$512 \text { bits } = 64 \text { bytes. } 64 \times ( 1 + 8 + 1 + 1 ) = 704 \text { bits }$

Exam 11: Data Networks

Using 128-bit addresses provides approximately $10 ^ { x }$ unique address, where x= _______.

Correct Answer
verified
\(2 ^ { 128 } = 2 ^ { 8 } \left( 2 ^ { 10 } \right) ^ { 12 } = 256 \left( 10 ^ { 3 } \right) ^ { 12 } = 256 \times 10 ^ { 36 } = 2.56 \times 10 ^ { 38 }\)

A 512-bit data file is to be transferred with asynchronous transmission packets that each contain a start bit, an 8-bit data byte, a parity bit, and one stop bit.How many bits are transmitted over achannel?

Correct Answer
verified
\(512 \text { bits } = 64 \text { bytes. } 64 \times ( 1 + 8 + 1 + 1 ) = 704 \text { bits }\)

Exam 11: Data Networks

Using 128-bit addresses provides approximately 10x10 ^ { x }10x unique address, where x= _______.

Correct Answerverified\(2 ^ { 128 } = 2 ^ { 8 } \left( 2 ^ { 10 } \right) ^ { 12 } = 256 \left( 10 ^ { 3 } \right) ^ { 12 } = 256 \times 10 ^ { 36 } = 2.56 \times 10 ^ { 38 }\)

A 512-bit data file is to be transferred with asynchronous transmission packets that each contain a start bit, an 8-bit data byte, a parity bit, and one stop bit.How many bits are transmitted over achannel?

Correct Answerverified\(512 \text { bits } = 64 \text { bytes. } 64 \times ( 1 + 8 + 1 + 1 ) = 704 \text { bits }\)

Using 128-bit addresses provides approximately $10 ^ { x }$ unique address, where x= _______.

Correct Answer
verified
\(2 ^ { 128 } = 2 ^ { 8 } \left( 2 ^ { 10 } \right) ^ { 12 } = 256 \left( 10 ^ { 3 } \right) ^ { 12 } = 256 \times 10 ^ { 36 } = 2.56 \times 10 ^ { 38 }\)

Correct Answer
verified
\(512 \text { bits } = 64 \text { bytes. } 64 \times ( 1 + 8 + 1 + 1 ) = 704 \text { bits }\)